JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
A force is represented by \(\mathrm{F}=a \mathrm{x}^2+\mathrm{bt}^{1 / 2}\). Where \(\mathrm{x}=\) distance and \(\mathrm{t}=\) time. The dimensions of \(\mathrm{b}^2 / \mathrm{a}\) are _______.
- A \(\left[\mathrm{ML}^3 \mathrm{~T}^{-3}\right]\)
- B \(\left[\mathrm{MLT}^{-2}\right]\)
- C \(\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]\)
- D \(\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\mathrm{ML}^3 \mathrm{~T}^{-3}\right]\)
Step-by-step Solution
Detailed explanation
\(\mathrm{F}=\mathrm{ax}^2+\mathrm{bt}^{1 / 2}\) \({[\mathrm{a}]=\frac{[\mathrm{F}]}{\left[\mathrm{x}^2\right]}=\left[\mathrm{M}^1 \mathrm{~L}^{-1} \mathrm{~T}^{-2}\right]}\)…
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