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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2023
  • Medium
  • Numerical

A convex lens of refractive index \(1.5\) and focal length \(18 cm\) in air is immersed in water. The change in focal length of the lens will be \(...........cm\).\(\left(\right.\) Given refractive index of water \(\left.=\frac{4}{3}\right)\)

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Correct Answer

(C) \(54\)

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\(\frac{ I }{ f _{ H _2 O }}=\left(\frac{\mu_{ g }}{\mu_{ H _2 O }}-1\right)\left(\frac{2}{ R }\right)\)

\(=\frac{1}{8}\left(\frac{2}{ R }\right)\)

\(=\frac{1}{\left(4 f _{\text {air }}\right)}\)

So, \(f _{ H _2 O }=4 f _{ air }=72\,cm\)

So change in focal length \(=72-18=54\,cm\)

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