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JEE Mains · Physics · STD 12 - 13. Nuclei
If \('f^{\prime}\) denotes the ratio of the number of nuclei decayed \(\left(N_{d}\right)\) to the number of nuclei at \(t=0\) \(\left({N}_{0}\right)\) then for a collection of radioactive nuclei, the rate of change of \('f'\) with respect to time is given as: \([\lambda\) is the radioactive decay constant]
- A \(\lambda\left(1-{e}^{-\lambda t}\right)\)
- B \(-\lambda e^{-\lambda t}\)
- C \(\lambda e^{-\lambda t}\)
- D \(-\lambda\left(1-{e}^{-\lambda . t}\right)\)
Answer & Solution
Correct Answer
(C) \(\lambda e^{-\lambda t}\)
Step-by-step Solution
Detailed explanation
\(N = N _{0} e ^{-\lambda t}\) \(N _{ d }= N _{0}- N\) \(N _{ d }= N _{0}\left(1- e ^{-\lambda t }\right)\) \(\frac{ N _{ d }}{ N _{0}}= f =1- e ^{-\lambda t }\) \(\frac{ df }{ dt }=\lambda e ^{-\lambda t }\)
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