Given a thin convex lens (refractive index \(\mu_2\) ), kept in a liquid (refractive index \(\mu_1, \mu_1 \lt \mu_2\) ) having radii of curvatures \(\left|R_1\right|\) and \(\left|R_2\right|\). Its second surface is silver polished. Where should an object be placed on the optic axis so that a real and inverted image is formed at the same place?

1. A \(\frac{\mu_1\left|\mathrm{R}_1\right| \cdot\left|\mathrm{R}_2\right|}{\mu_2\left(\left|\mathrm{R}_1\right|+\left|\mathrm{R}_2\right|\right)-\mu_1\left|\mathrm{R}_2\right|}\)
2. B \(\frac{\mu_1\left|\mathrm{R}_1\right| \cdot\left|\mathrm{R}_2\right|}{\mu_2\left(\left|\mathrm{R}_1\right|+\left|\mathrm{R}_2\right|\right)-\mu_1\left|\mathrm{R}_1\right|}\)
3. C \(\frac{\left(\mu_2+\mu_1\right)\left|\mathrm{R}_1\right|}{\left(\mu_2-\mu_1\right)}\)
4. D \(\frac{\mu_1\left|\mathrm{R}_1\right| \cdot\left|\mathrm{R}_2\right|}{\mu_2\left(2\left|\mathrm{R}_1\right|+\left|\mathrm{R}_2\right|\right)-\mu_1 \sqrt{\left|\mathrm{R}_1\right| \cdot\left|\mathrm{R}_2\right|}}\)