JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
A proton and an electron have the same de Broglie wavelength. If \(K_p\) and \(K_e\) be the kinetic energies of proton and electron respectively. Then choose the correct relation :
- A \(\mathrm{K}_{\mathrm{p}}>\mathrm{K}_{\mathrm{e}}\)
- B \(\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{e}}\)
- C \(\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{e}}^2\)
- D \(\mathrm{K}_{\mathrm{p}}<\mathrm{K}_{\mathrm{e}}\)
Answer & Solution
Correct Answer
(D) \(\mathrm{K}_{\mathrm{p}}<\mathrm{K}_{\mathrm{e}}\)
Step-by-step Solution
Detailed explanation
De Broglie wavelength of proton & electron \(=\lambda\) \(\because \lambda=\frac{\mathrm{h}}{\mathrm{p}}\) \(\therefore \mathrm{p}_{\text {proton }}=\mathrm{p}_{\text {electron }}\) \(\because \mathrm{KE}=\frac{\mathrm{p}^2}{2 \mathrm{~m}}\)…
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