JEE Mains · Physics · STD 12 - Moving charges and magnetism
- JEE Mains 2022
- Medium
- MCQ
A wire \(X\) of length \(50\; cm\) carrying a current of \(2\,A\) is placed parallel to a long wire \(Y\) of length \(5\,m\). The wire \(Y\) carries a current of \(3\,A\). The distance between two wires is \(5\,cm\) and currents flow in the same direction. The force acting on the wire \(Y\) is.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(1.2 \times 10^{-5} \;N\) directed towards wire \(X\).
Step-by-step Solution
Detailed explanation
Force of interaction \(=I_{1} \ell_{1} B_{12}\)
\(=\frac{\mu_{0} I _{1} I _{2}}{2 \pi r } \ell_{1}\)
\(=\frac{4 \pi \times 10^{-7} \times 6 \times 5}{2 \pi \times 5 \times 10^{-2}}\)
\(=1.2 \times 10^{-5} \text { towards } X\)
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