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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2024
  • Hard
  • MCQ

Average force exerted on a non-reflecting surface at normal incidence is \(2.4 \times 10^{-4} \mathrm{~N}\). If \(360 \mathrm{~W} / \mathrm{cm}^2\) is the light energy flux during span of \(1\) hour \(30\) minutes. Then the area of the surface is _______.

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Answer & Solution

Correct Answer

(B) \(0.02 \mathrm{~m}^2\)

Step-by-step Solution

Detailed explanation

\(\text { Pressure }=\frac{I}{C}=\frac{F}{A}\)

\(\Rightarrow \frac{360}{10^{-4} \times 3 \times 10^8}=\frac{2.4 \times 10^{-4}}{A}\)

\(\Rightarrow A=2 \times 10^{-2} \mathrm{~m}^2=0.02 \mathrm{~m}^2\)

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