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JEE Mains · Physics · STD 12 - 8. Electromagnetic waves

A plane EM wave is propagating along \(\mathrm{x}\) direction. It has a wavelength of \(4 \mathrm{~mm}\). If electric field is in y direction with the maximum magnitude of \(60 \mathrm{Vm}^{-1}\), the equation for magnetic field is _______.

  1. A \(\mathrm{B}_z=60 \sin \left[\frac{\pi}{2}\left(\mathrm{x}-3 \times 10^8 \mathrm{t}\right)\right] \hat{\mathrm{kT}}\)
  2. B \(\mathrm{B}_z=2 \times 10^{-7} \sin \left[\frac{\pi}{2} \times 10^3\left(\mathrm{x}-3 \times 10^8 \mathrm{t}\right)\right] \hat{\mathrm{kT}}\)
  3. C \(\mathrm{B}_{\mathrm{x}}=60 \sin \left[\frac{\pi}{2}\left(\mathrm{x}-3 \times 10^8 \mathrm{t}\right)\right]\) i \(\mathrm{i} \mathrm{T}\)
  4. D \(\mathrm{B}_z=2 \times 10^{-7} \sin \left[\frac{\pi}{2}\left(\mathrm{x}-3 \times 10^8 \mathrm{t}\right)\right] \hat{\mathrm{k} T}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\mathrm{B}_z=2 \times 10^{-7} \sin \left[\frac{\pi}{2} \times 10^3\left(\mathrm{x}-3 \times 10^8 \mathrm{t}\right)\right] \hat{\mathrm{kT}}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{E}=\mathrm{BC} \Rightarrow 60=\mathrm{B} \times 3 \times 10^8\) \(\Rightarrow \mathrm{B}=2 \times 10^{-7}\) \(\text { Also } \mathrm{C}=\mathrm{f} \lambda\) \(\Rightarrow 3 \times 10^8=\mathrm{f} \times 4 \times 10^{-3}\)…
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