JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
An alternating voltage of amplitude \(40 \mathrm{~V}\) and frequency \(4 \mathrm{kHz}\) is applied directly across the capacitor of \(12 \mu \mathrm{F}\). The maximum displacement current between the plates of the capacitor is nearly _______.
- A \(13 \mathrm{~A}\)
- B \(8 \mathrm{~A}\)
- C \(10 \mathrm{~A}\)
- D \(12 \mathrm{~A}\)
Answer & Solution
Correct Answer
(D) \(12 \mathrm{~A}\)
Step-by-step Solution
Detailed explanation
Displacement current is same as conduction current in capacitor. \(\mathrm{x}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}=\frac{1}{2 \pi \mathrm{fC}}\) \(=\frac{1}{2 \pi \times 4 \times 10^3 \times 12 \times 10^{-6}}=3.317 \Omega\) \(I=\frac{V}{X_C}=\frac{40}{3.317}=12 \mathrm{~A}\)
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