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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter

An \(\alpha\) particle and a carbon \(12\) atom has same kinetic energy \(K\). The ratio of their de-Broglie wavelength \(\left(\lambda_{a}: \lambda_{C 12}\right)\) is

  1. A \(1: \sqrt{3}\)
  2. B \(\sqrt{3}: 1\)
  3. C \(3: 1\)
  4. D \(2: \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\sqrt{3}: 1\)

Step-by-step Solution

Detailed explanation

\(k=\frac{P^{2}}{2 m} \Rightarrow P \alpha \sqrt{m}\) Now \(\lambda=\frac{h}{p}\) So, \(\lambda \alpha \frac{1}{p} \Rightarrow \lambda \alpha \frac{1}{\sqrt{m}}\) \(\frac{\lambda_{\alpha}}{\lambda_{C 12}}=\frac{\sqrt{3}}{1}\)
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