A parallel beam of electrons travelling in \(x-\) direction falls on a slit of width \(d\) (see figure) . If after passing the slit, an electron acquires momentum \(P_y\) in the \(y-\) direction then for a majority of electrons passing through the slit ( \(h\) is Planck's constant)

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Answer & Solution

Correct Answer

(A) \(\left| {{P_y}} \right|d > h\)

Detailed explanation

From Bragg's equation

\(d \sin \theta=\lambda\)

\(\sin \theta=\frac{\lambda}{d}<1\)

\(\therefore \lambda < d\)

\(\frac{h}{{\left| {{p_y}} \right|}} < d\) \(\left[ {\because \lambda = \frac{h}{{\left| {{p_y}} \right|}}} \right]\)

\(\therefore \quad h<\left|p_{y}\right| d\)

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