JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2016
- Medium
- MCQ
Two stars are \(10\) light years away from the earth. They are seen through a telescope of objective diameter \(30\, cm\). The wavelength of light is \(600\, nm\). To see the stars just resolved by the telescope, the minimum distance between them should be ( \(1\) light year \(= 9.46 \times 10^{15}\, m\)) of the order of
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(10^8\,km\)
Step-by-step Solution
Detailed explanation
We know that \(\Delta \theta=\frac{1.22 \lambda}{D}=\frac{l}{R}\)
The minimum distance between them
\(l=\frac{9.46 \times 10^{15} \times 10 \times 1.22 \times 600 \times 10^{-9}}{0.3}\)
\(=2308.24 \times 10^{8}\, \mathrm{m}\)
\(\Rightarrow 2.308 \times 10^{8}\, \mathrm{km}\)
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