JEE Mains · Physics · STD 11 - Friction
- JEE Mains 2023
- Hard
- MCQ
A bullet of mass \(0.1\,kg\) moving horizontally with speed \(400\,ms ^{-1}\) hits a wooden block of mass \(3.9\,kg\) kept on a horizontal rough surface. The bullet gets embedded into the block and moves \(20\,m\) before coming to rest. The coefficient of friction between the block and the surface is \(........\) \(\left(\text { Given } g=10 \,ms ^2\right. \text { ) }\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(0.25\)
Step-by-step Solution
Detailed explanation
\(P _{ i }= P _{ f }(\text { Collision })\)
\(\Rightarrow(0.1)(400)=(0.1+3.9) v\)
\(\Rightarrow v =\frac{0.1 \times 400}{4}=10\,m / s\)
\(a =\frac{\mu mg }{ m }=\mu g\)
Apply equation of motion,
\(v ^2=u^2+2 as\)
\(\Rightarrow 0=(10)^2-2 \mu g \times 20\)
\(\Rightarrow 40 \mu g =100\)
\(\Rightarrow \mu=\frac{100}{2 \times 10 \times 20}=\frac{1}{4}\)
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