JEE Mains · Physics · STD 11 - 11. thermodynamics
A monoatomic gas at pressure \(P\) and volume \(V\) is suddenly compressed to one eighth of its original volume. The final pressure at constant entropy will be \(.....P\)
- A \(1\)
- B \(8\)
- C \(32\)
- D \(64\)
Answer & Solution
Correct Answer
(C) \(32\)
Step-by-step Solution
Detailed explanation
Constant entropy means process is adiabatic \(PV ^{\gamma}=\) constant \(V _{2}=\frac{ V _{1}}{8}\) \(P _{1} V _{1}^{\gamma}= P _{2} V _{2}^{\gamma}\) \(P _{1} V _{1}^{\gamma}= P _{2}\left(\frac{ V _{1}}{8}\right)^{5 / 3}\)…
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