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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2022
  • Medium
  • Numerical

A heat engine operates with the cold reservoir at temperature \(324 K\). The minimum temperature of the hot reservoir, if the heat engine takes \(300 \; J\) heat from the hot reservoir and delivers \(180 \; J\) heat to the cold reservoir per cycle, is \(\dots \; K .\)

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Answer & Solution

Correct Answer

(B) \(540\)

Step-by-step Solution

Detailed explanation

\(T _{ c }=324 \; k\)

\(T _{ H }= ?\)

\(Q _{ H }=300 \; J\)

\(Q _{ L }=180 \; J\)

\(1-\frac{ Q _{ L }}{ Q _{ H }}=1-\frac{ T _{ L }}{ T _{ H }}\)

\(\frac{ Q _{ L }}{ Q _{ H }}=\frac{ T _{ L }}{ T _{ H }}\)

\(T _{ H }=\frac{ Q _{ H }}{ Q _{ L }} \times T _{ L }=\frac{300}{180} \times 324=540 K\)

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