JEE Mains · Physics · STD 11 - 11. thermodynamics
A heat engine operates with the cold reservoir at temperature \(324 K\). The minimum temperature of the hot reservoir, if the heat engine takes \(300 \; J\) heat from the hot reservoir and delivers \(180 \; J\) heat to the cold reservoir per cycle, is \(\dots \; K .\)
- A \(530\)
- B \(540\)
- C \(550\)
- D \(560\)
Answer & Solution
Correct Answer
(B) \(540\)
Step-by-step Solution
Detailed explanation
\(T _{ c }=324 \; k\) \(T _{ H }= ?\) \(Q _{ H }=300 \; J\) \(Q _{ L }=180 \; J\) \(1-\frac{ Q _{ L }}{ Q _{ H }}=1-\frac{ T _{ L }}{ T _{ H }}\) \(\frac{ Q _{ L }}{ Q _{ H }}=\frac{ T _{ L }}{ T _{ H }}\)…
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