JEE Mains · Physics · STD 11 - Thermodynamics
- JEE Mains 2022
- Medium
- Numerical
A heat engine operates with the cold reservoir at temperature \(324 K\). The minimum temperature of the hot reservoir, if the heat engine takes \(300 \; J\) heat from the hot reservoir and delivers \(180 \; J\) heat to the cold reservoir per cycle, is \(\dots \; K .\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(540\)
Step-by-step Solution
Detailed explanation
\(T _{ c }=324 \; k\)
\(T _{ H }= ?\)
\(Q _{ H }=300 \; J\)
\(Q _{ L }=180 \; J\)
\(1-\frac{ Q _{ L }}{ Q _{ H }}=1-\frac{ T _{ L }}{ T _{ H }}\)
\(\frac{ Q _{ L }}{ Q _{ H }}=\frac{ T _{ L }}{ T _{ H }}\)
\(T _{ H }=\frac{ Q _{ H }}{ Q _{ L }} \times T _{ L }=\frac{300}{180} \times 324=540 K\)
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