JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A man of \(60\,kg\) is running on the road and suddenly jumps into a stationary trolly car of mass \(120\,kg\). Then. the trolly car starts moving with velocity \(2\,ms ^{-1}\). The velocity of the running man was _________\(ms ^{-1}\). when he jumps into the car
- A \(5\)
- B \(6\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(6\)
Step-by-step Solution
Detailed explanation
Taking the system as man and trolley and using conservation of linear momentum. \(60 \times v =(60+120) \times 2\) \(\Rightarrow v =6 \,m / s\)
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