JEE Mains · Physics · STD 12 - 3. current electricity
A current of \(6\, A\) enters one corner \(P\) of an equilateral triangle \(PQR\) having \(3\) wires of resistance \(2 \,\Omega\) each and leaves by the corner \(R\). The currents \(i_{1}\) in ampere is ........ .
- A \(2\)
- B \(1\)
- C \(3\)
- D \(5\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
For parallel combination current devides in the inverse ratio of resistance. \(i _{ PQ }=\frac{2}{6} \times 6 \,A\)
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