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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
- JEE Mains 2014
- Hard
- MCQ
A photon of wavelength \(\lambda \) is scattered from an electron, which was at rest. The wavelength shift \(\Delta \lambda \) is three times of \( \lambda \) and the angle of scattering \(\theta \) is \(60^o\) . The angle at which the electron recoiled is \(\phi \). The value of \(tan\,\phi \) is : ( electron speed is much smaller than the speed of light)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(0.25\)
Step-by-step Solution
Detailed explanation
\(\Delta P{\text{ }} = (P\,\,\cos \,\,60\hat i + P\sin \,\,60\hat j) - 4P\hat i\)
\( = - \frac{{7P}}{2}\hat i + \frac{{\sqrt 3 P}}{2}\hat j \Rightarrow \) \(\tan \phi = \frac{{\sqrt 3 }}{7},\,\,\tan \phi = 0.25\)
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