JEE Mains · Physics · STD 12 -7. Alternating current
In an \(A.C.\) circuit, the instantaneous \(e.m.f\) and current are given by. \(e=100\) \(sin\) \(20t\) \(i=20sin\) \(\left( {30t - \frac{\pi }{4}} \right)\) In one cycle of \(A.C.\), the average power consumed by the circuit and the wattless current are, respectively
- A \(\frac{{1000}}{{\sqrt 2 }},10\)
- B \(\;\frac{{50}}{{\sqrt 2 }},0\)
- C \(50,0\)
- D \(50,10\)
Answer & Solution
Correct Answer
(A) \(\frac{{1000}}{{\sqrt 2 }},10\)
Step-by-step Solution
Detailed explanation
As we know, average power \(P_{\text {avg }}=V_{\text {ms }} I_{\text {ms }} \cos \theta\)…
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