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JEE Mains · Physics · STD 11 - Work,energy,power and collision
  • JEE Mains 2016
  • Medium
  • MCQ

A particle of mass \(M\) is moving in a circle of fixed radius \(R\) in such a way that its centripetal acceleration at time \(t\) is given by \(n^2Rt^2\) where \(n\) is a constant. The Power delivered to the particle by the force acting on it, is

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Answer & Solution

Correct Answer

(B) \(M\,{n^2}{R^2}{t^2}\)

Step-by-step Solution

Detailed explanation

\(v = \sqrt{a_c R}\)

\(v = \sqrt{(n^2Rt^2)R} = \sqrt{n^2R^2t^2} = nRt\)

\(a_t = \frac{dv}{dt} = \frac{d}{dt}(nRt) = nR\)

\(P = F_t v = (Ma_t)v = (MnR)(nRt)\)

\(P = Mn^2R^2t\)

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