JEE Mains · Physics · STD 11 - 10.2 transmission of heat
A metallic sphere cools from \(50^{\circ} C\) to \(40^{\circ} C\) in \(300 \,s.\) If atmospheric temperature around is \(20^{\circ} C ,\) then the sphere's temperature after the next \(5\) minutes will be close to\(.....C\)
- A \(33\)
- B \(35\)
- C \(31\)
- D \(28\)
Answer & Solution
Correct Answer
(A) \(33\)
Step-by-step Solution
Detailed explanation
\(\frac{50-40}{300}=\beta\left(\frac{50+40}{2}-20\right)\) \(\frac{40-T}{300}=\beta\left(\frac{40+T}{2}-20\right)\) \(\therefore \quad T=\frac{100}{3}\)
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