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JEE Mains · Physics · STD 11 - Transmission of heat
  • JEE Mains 2020
  • Medium
  • MCQ

A metallic sphere cools from \(50^{\circ} C\) to \(40^{\circ} C\) in \(300 \,s.\) If atmospheric temperature around is \(20^{\circ} C ,\) then the sphere's temperature after the next \(5\) minutes will be close to\(.....C\)

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Answer & Solution

Correct Answer

(A) \(33\)

Step-by-step Solution

Detailed explanation

\(\frac{50-40}{300}=\beta\left(\frac{50+40}{2}-20\right)\)

\(\frac{40-T}{300}=\beta\left(\frac{40+T}{2}-20\right)\)

\(\therefore \quad T=\frac{100}{3}\)

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