JEE Mains · Physics · STD 11- Mechanical properties of solids
- JEE Mains 2020
- Medium
- MCQ
Two steel wires having same length are suspended from a ceiling under the same load. If the ratio of their energy stored per unit volume is \(1: 4,\) the ratio of their diameters is
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) \(\sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
\(\frac{\text { Energystored }}{\text { Volume }}=\frac{1}{2} \frac{(\text { Stress })^{2}}{\mathrm{Y}}\)
\(\frac{\mathrm{u}_{1}}{\mathrm{u}_{2}}=\frac{1}{4} \Rightarrow 4 \mathrm{u}_{1}=\mathrm{u}_{2}\)
\(4 \frac{1}{2 \mathrm{Y}}\left[\frac{\mathrm{W} \cdot 4}{\pi \mathrm{d}_{1}^{2}}\right]^{2}=\frac{1}{2 \mathrm{Y}}\left[\frac{\mathrm{W} \cdot 4}{\pi \mathrm{d}_{2}^{2}}\right]^{2}\)
\(4=\left(\frac{\mathrm{d}_{1}}{\mathrm{d}_{2}}\right)^{4}\)
\(\Rightarrow \frac{\mathrm{d}_{1}}{\mathrm{d}_{2}}=\sqrt{2}: 1\)
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