JEE Mains · Physics · STD 11- 8. mechanical properties of solids
Two steel wires having same length are suspended from a ceiling under the same load. If the ratio of their energy stored per unit volume is \(1: 4,\) the ratio of their diameters is
- A \(1: \sqrt{2}\)
- B \(1: 2\)
- C \(2:1\)
- D \(\sqrt{2}: 1\)
Answer & Solution
Correct Answer
(D) \(\sqrt{2}: 1\)
Step-by-step Solution
Detailed explanation
\(\frac{\text { Energystored }}{\text { Volume }}=\frac{1}{2} \frac{(\text { Stress })^{2}}{\mathrm{Y}}\) \(\frac{\mathrm{u}_{1}}{\mathrm{u}_{2}}=\frac{1}{4} \Rightarrow 4 \mathrm{u}_{1}=\mathrm{u}_{2}\)…
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