JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
For the circuit shown below, the current through the Zener diode is......\(mA\)
- A \(9\)
- B \(5\)
- C \(0\)
- D \(14\)
Answer & Solution
Correct Answer
(A) \(9\)
Step-by-step Solution
Detailed explanation
\(\mathrm{I}_{10 \mathrm{k}}=\frac{50}{10 \mathrm{k}}=5\, \mathrm{mA}\) \(\mathrm{i}_{5 \mathrm{k}}=\frac{120-50}{5 \mathrm{k}}=14\, \mathrm{mA}\) \(\mathrm{i}_{2}=(14-5) \mathrm{mA}=9\, \mathrm{mA}\)
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