JEE Mains · Physics · STD 11 - 4.1 newtons laws of motion
A light string passing over a smooth light pulley connects two blocks of masses \(m_1\) and \(m_2\) (where \(m_2>m_1\) ). If the acceleration of the system is \(\frac{\mathrm{g}}{\sqrt{2}}\), then the ratio of the masses \(\frac{\mathrm{m}_1}{\mathrm{~m}_2}\) is _______.
- A \(\frac{\sqrt{2}-1}{\sqrt{2}+1}\)
- B \(\frac{1+\sqrt{5}}{\sqrt{5}-1}\)
- C \(\frac{1+\sqrt{5}}{\sqrt{2}-1}\)
- D \(\frac{\sqrt{3}+1}{\sqrt{2}-1}\)
Answer & Solution
Correct Answer
(A) \(\frac{\sqrt{2}-1}{\sqrt{2}+1}\)
Step-by-step Solution
Detailed explanation
\(a=\left(\frac{M_2-M_1}{M_1+M_2}\right) g\) \(\frac{g}{\sqrt{2}}=\left(\frac{M_2-M_1}{M_1+M_2}\right) \mathrm{g}\) \(\left(M_1+M_2\right)=\sqrt{2} M_2-\sqrt{2} M_1\) \(\frac{M_1}{M_2}=\left(\frac{\sqrt{2}-1}{\sqrt{2}+1}\right)\)
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