ExamBro
ExamBro
JEE Mains · Physics · STD 11 - Oscillations
  • JEE Mains 2021
  • Medium
  • MCQ

Time period of a simple pendulum is \(T\) inside a lift when the lift is stationary. If the lift moves upwards with an acceleration \(g / 2,\) the time period of pendulum will be

Pick an option to check your answer.
Verified Solution

Answer & Solution

Correct Answer

(D) \(\sqrt{\frac{2}{3}} T\)

Step-by-step Solution

Detailed explanation

When lift is stationary

\(T =2 \pi \sqrt{\frac{ L }{ g }}\)

When lift is moving upwards \(\Rightarrow\) Pseudo force acts downwards

\(\Rightarrow g _{ eff }= g +\frac{ g }{2}=\frac{3 g }{2}\)

\(\Rightarrow\) New time period

\(T ^{4}=2 \pi \sqrt{\frac{ L }{ g _{ eff }}}=2 \pi \sqrt{\frac{2 L }{3 g }}\)

\(T ^{\prime}=\sqrt{\frac{2}{3}} T\)

Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app