JEE Mains · Physics · STD 11 - 13. oscillations
Time period of a simple pendulum is \(T\) inside a lift when the lift is stationary. If the lift moves upwards with an acceleration \(g / 2,\) the time period of pendulum will be
- A \(\sqrt{3} T\)
- B \(\frac{ T }{\sqrt{3}}\)
- C \(\sqrt{\frac{3}{2}} T\)
- D \(\sqrt{\frac{2}{3}} T\)
Answer & Solution
Correct Answer
(D) \(\sqrt{\frac{2}{3}} T\)
Step-by-step Solution
Detailed explanation
When lift is stationary \(T =2 \pi \sqrt{\frac{ L }{ g }}\) When lift is moving upwards \(\Rightarrow\) Pseudo force acts downwards \(\Rightarrow g _{ eff }= g +\frac{ g }{2}=\frac{3 g }{2}\) \(\Rightarrow\) New time period…
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