JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
A point dipole \(\vec p = - {p_0}\hat x\) is kept at the origin. The potential and electric field due to this dipole on the \(y-\) axis at a distance \(d\) are, respectively : (Take \(V = 0\) at infinity)
- A \(\frac{{\left| {\vec p} \right|}}{{4\pi {\varepsilon _0}{d^2}}},\frac{{ -\vec p}}{{4\pi {\varepsilon _0}{d^3}}}\)
- B \(0,\frac{{ \vec p}}{{4\pi {\varepsilon _0}{d^3}}}\)
- C \(\frac{{\left| {\vec p} \right|}}{{4\pi {\varepsilon _0}{d^2}}},\frac{{ \vec p}}{{4\pi {\varepsilon _0}{d^3}}}\)
- D \(0,\frac{{ - \vec p}}{{4\pi {\varepsilon _0}{d^3}}}\)
Answer & Solution
Correct Answer
(D) \(0,\frac{{ - \vec p}}{{4\pi {\varepsilon _0}{d^3}}}\)
Step-by-step Solution
Detailed explanation
\(V=0\) \(E=-\frac{K \vec{P}}{r^{3}}\) \(=-\frac{\vec{p}}{4 \pi \varepsilon_{0} d^{3}}\)
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