JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
A uniform cylindrical rod of length \(L\) and radius \(r\), is made from a material whose Young's modulus of Elasticity equals \(Y\). When this rod is heated by temperature \(T\) and simultaneously subjected to a net longitudinal compressional force \(F\), its length remains unchanged. The coefficient of volume expansion, of the material of the rod, is (nearly) equals to
- A \(9F/\left( {\pi {r^2}YT} \right)\)
- B \(F/\left( {3\pi {r^2}YT} \right)\)
- C \(3F/\left( {\pi {r^2}YT} \right)\)
- D \(6F/\left( {\pi {r^2}YT} \right)\)
Answer & Solution
Correct Answer
(C) \(3F/\left( {\pi {r^2}YT} \right)\)
Step-by-step Solution
Detailed explanation
Lenght of cylinder remains unchanged So \({\left( {\frac{F}{A}} \right)_{compressive}} = {\left( {\frac{F}{A}} \right)_{Themal}}\) \(\frac{F}{{\pi {r^2}}} = Y\alpha T\,\,\,\,\,\,\left( {\alpha \,is\,liner\,coefficient\,of\,\exp ansion} \right)\)…
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