JEE Mains · Physics · STD 11 - 13. oscillations
The frequency of oscillation of a mass \(m\) suspended by a spring is \(v_1\). If the length of the spring is cut to half, the same mass oscillates with frequency \(v_2\). The value of \(v_2/v_1\) is ________.
- A \(1\)
- B \(2\)
- C \(\sqrt{2}\)
- D \(\sqrt{3}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{2}\)
Step-by-step Solution
Detailed explanation
The frequency of oscillation of a spring-mass system is given by \(v = \dfrac{1}{2\pi} \sqrt{\dfrac{k}{m}}\), where \(k\) is the spring constant and \(m\) is the mass. The spring constant \(k\) is inversely proportional to the length of the spring \(L\), so…
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