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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2019
  • Hard
  • MCQ

An \(NPN\) transistor is used in common emitter configuration as an amplifier with \(1\,k\Omega \) load resistance. Signal voltage of \(10\,mV\) is applied across the base emitter. This produces a \(3\,mA\) change in the collector current and \(15\,\mu A\) change in the base current of the amplifier. The input resistance and voltage gain are

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Answer & Solution

Correct Answer

(A) \(0.67\,k\Omega ,300\)

Step-by-step Solution

Detailed explanation

Input current \(=15 \times 10^{-6}\)

Output current \(=3 \times 10^{-3}\)

Resistance out put \(=1000\)

\(\mathrm{V}_{\text {input }}=10 \times 10^{-3}\)

Now \(V_{input}\) \(=\) \(r_{input}\) \(\times\) \(i_{input}\)

\(10 \times 10^{-3}=r_{\text {input }} \times 15 \times 10^{-6}\)

\(r_{\text {input }}=\frac{2000}{3}=\) \(0.67\,k\Omega ,\)

Voltage gain \(=\frac{V_{\text {output }}}{V_{\text {input }}}=\frac{1000 \times 3 \times 10^{-3}}{10 \times 10^{-3}}=300\)

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