JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2019
- Hard
- MCQ
An \(NPN\) transistor is used in common emitter configuration as an amplifier with \(1\,k\Omega \) load resistance. Signal voltage of \(10\,mV\) is applied across the base emitter. This produces a \(3\,mA\) change in the collector current and \(15\,\mu A\) change in the base current of the amplifier. The input resistance and voltage gain are
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Answer & Solution
Correct Answer
(A) \(0.67\,k\Omega ,300\)
Step-by-step Solution
Detailed explanation
Input current \(=15 \times 10^{-6}\)
Output current \(=3 \times 10^{-3}\)
Resistance out put \(=1000\)
\(\mathrm{V}_{\text {input }}=10 \times 10^{-3}\)
Now \(V_{input}\) \(=\) \(r_{input}\) \(\times\) \(i_{input}\)
\(10 \times 10^{-3}=r_{\text {input }} \times 15 \times 10^{-6}\)
\(r_{\text {input }}=\frac{2000}{3}=\) \(0.67\,k\Omega ,\)
Voltage gain \(=\frac{V_{\text {output }}}{V_{\text {input }}}=\frac{1000 \times 3 \times 10^{-3}}{10 \times 10^{-3}}=300\)
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