JEE Mains · Physics · STD 12 - 3. current electricity
A potentiometer wire \(AB\) having length \(L\) and resistance \(12\, r\) is joined to a cell \(D\) of \(emf\) \(\varepsilon \) and internal resistance \(r\). A cell \(C\) having \(emf\) \(\varepsilon /2\) and internal resistance \(3r\) is connected. The length \(AJ\) at which the galvanometer as shown in figure shows no deflection is

- A \(\frac{{11}}{{12}}\,L\)
- B \(\frac{{11}}{{24}}\,L\)
- C \(\frac{{13}}{{24}}\,L\)
- D \(\frac{{5}}{{12}}\,L\)
Answer & Solution
Correct Answer
(C) \(\frac{{13}}{{24}}\,L\)
Step-by-step Solution
Detailed explanation
\(V_{A J}=I R_{A J}\) \(\frac{E}{3}=\left(\frac{E}{12 r+3 r}\right) \times\left(\frac{x}{L} \times 12 r\right)\)
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