JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2022
- Medium
- MCQ
The dimension of mutual inductance is ............
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(\left[ ML ^{2} T ^{-2} A ^{-2}\right]\)
Step-by-step Solution
Detailed explanation
\(e _{2}\) : induced emf in secondary coil
\(i _{1}:\) Current in primary coil
\(M\) : Mutual inductance
\(e _{2}=- M \frac{ di _{1}}{ dt }\)
\(M =-\frac{ e _{2}}{\frac{ di }{ dt }}\)
\({[ M ]=\frac{\left[ e _{2}\right]}{\left[\frac{ di _{1}}{ dt }\right]}=\frac{\left[\frac{ W }{ q }\right]}{\left[\frac{ di _{1} }{ dt }\right]}=\frac{\left[ ML ^{2} T ^{-2}\right]}{\left[ \frac {AT}{AT^{-1}}\right]}}\)
\(=\left[ ML ^{2} T ^{-2} A ^{-2}\right]\)
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