JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
The dimension of mutual inductance is ............
- A \(\left[ ML ^{2} T ^{-2} A ^{-1}\right]\)
- B \(\left[ ML ^{2} T ^{-3} A ^{-1}\right]\)
- C \(\left[ ML ^{2} T ^{-2} A ^{-2}\right]\)
- D \(\left[ ML ^{2} T ^{-3} A ^{-2}\right]\)
Answer & Solution
Correct Answer
(C) \(\left[ ML ^{2} T ^{-2} A ^{-2}\right]\)
Step-by-step Solution
Detailed explanation
\(e _{2}\) : induced emf in secondary coil \(i _{1}:\) Current in primary coil \(M\) : Mutual inductance \(e _{2}=- M \frac{ di _{1}}{ dt }\) \(M =-\frac{ e _{2}}{\frac{ di }{ dt }}\)…
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