JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2021
- Medium
- MCQ
A certain charge \(Q\) is divided into two parts \(q\) and \((Q-q) .\) How should the charges \(Q\) and \(q\) be divided so that \(q\) and \((Q-q)\) placed at a certain distance apart experience maximum electrostatic repulsion?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(Q=2 q\)
Step-by-step Solution
Detailed explanation
\(F=\frac{k Q(Q-q)}{\pi^{2}}\)
\(\frac{d F}{d q}=0\) When force is maximum
\(\frac{d F}{d q}=\frac{k}{L^{2}}[Q-2 q]=0\)
\(\Rightarrow Q-2 q=0 \Rightarrow Q=2 q\)
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