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JEE Mains · Physics · STD 12 - 1. Electric charges and fields

A certain charge \(Q\) is divided into two parts \(q\) and \((Q-q) .\) How should the charges \(Q\) and \(q\) be divided so that \(q\) and \((Q-q)\) placed at a certain distance apart experience maximum electrostatic repulsion?

  1. A \({Q}=\frac{{q}}{2}\)
  2. B \({Q}=3 {q}\)
  3. C \(Q=2 q\)
  4. D \(Q=4 q\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(Q=2 q\)

Step-by-step Solution

Detailed explanation

\(F=\frac{k Q(Q-q)}{\pi^{2}}\) \(\frac{d F}{d q}=0\) When force is maximum \(\frac{d F}{d q}=\frac{k}{L^{2}}[Q-2 q]=0\) \(\Rightarrow Q-2 q=0 \Rightarrow Q=2 q\)
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