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JEE Mains · Physics · STD 12 - Electric charges and fields
  • JEE Mains 2021
  • Medium
  • MCQ

A certain charge \(Q\) is divided into two parts \(q\) and \((Q-q) .\) How should the charges \(Q\) and \(q\) be divided so that \(q\) and \((Q-q)\) placed at a certain distance apart experience maximum electrostatic repulsion?

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Answer & Solution

Correct Answer

(C) \(Q=2 q\)

Step-by-step Solution

Detailed explanation

\(F=\frac{k Q(Q-q)}{\pi^{2}}\)

\(\frac{d F}{d q}=0\) When force is maximum

\(\frac{d F}{d q}=\frac{k}{L^{2}}[Q-2 q]=0\)

\(\Rightarrow Q-2 q=0 \Rightarrow Q=2 q\)

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