JEE Mains · Physics · STD 12 -Alternating current
- JEE Mains 2020
- Hard
- MCQ
In \(LC\) circuit the inductance \(\mathrm{L}=40\; \mathrm{mH}\) and capacitance \(\mathrm{C}=100\; \mu \mathrm{F} .\) If a voltage \(\mathrm{V}(\mathrm{t})=10 \sin (314 \mathrm{t})\) is applied to the circuit, the current in the circuit is given as
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(0.52 \cos 314 t\)
Step-by-step Solution
Detailed explanation
\(\mathrm{X}_{\mathrm{L}}=\omega \mathrm{L}=314 \times 40 \times 10^{-3}=12.56 \Omega\)
\(\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}=\frac{1}{314 \times 100 \times 10^{-6}}\)
\(=\frac{10^{4}}{314}=31.84 \Omega\)
\(\mathrm{V}_{\mathrm{m}}=\mathrm{I}_{\mathrm{m}}\left(\mathrm{X}_{\mathrm{C}}-\mathrm{X}_{\mathrm{L}}\right)\)
\(10=\mathrm{I}_{\mathrm{m}}(31.84-12.56)\)
\(I_{m}=\frac{10}{19.28}=0.52 A\)
\(I=0.52 \sin \left(314 t+\frac{\pi}{2}\right)\)
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