ExamBro
ExamBro
JEE Mains · Physics · STD 12 -7. Alternating current

In \(LC\) circuit the inductance \(\mathrm{L}=40\; \mathrm{mH}\) and capacitance \(\mathrm{C}=100\; \mu \mathrm{F} .\) If a voltage \(\mathrm{V}(\mathrm{t})=10 \sin (314 \mathrm{t})\) is applied to the circuit, the current in the circuit is given as 

  1. A \(0.52 \cos 314 t\)
  2. B \(0.52 \sin 314 t\)
  3. C \(10 \cos 314 t\)
  4. D \(5.2 \cos 314 t\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.52 \cos 314 t\)

Step-by-step Solution

Detailed explanation

\(\mathrm{X}_{\mathrm{L}}=\omega \mathrm{L}=314 \times 40 \times 10^{-3}=12.56 \Omega\) \(\mathrm{X}_{\mathrm{C}}=\frac{1}{\omega \mathrm{C}}=\frac{1}{314 \times 100 \times 10^{-6}}\) \(=\frac{10^{4}}{314}=31.84 \Omega\)…
Same subject
Explore more questions on app