JEE Mains · Physics · STD 12 -7. Alternating current
A series LCR circuit with \(R = 20\ \Omega\), \(L = 1.6\text{ H}\) and \(C = 40\ \mu\text{F}\) is connected to a variable frequency a.c. source. The inductive reactance at resonant frequency is _______ \(\Omega\).
- A 600
- B 400
- C 300
- D 200
Answer & Solution
Correct Answer
(D) 200
Step-by-step Solution
Detailed explanation
Given \(L = 1.6\text{ H}\) and \(C = 40\ \mu\text{F} = 40 \times 10^{-6}\text{ F}\). At resonance, the angular frequency is \(\omega_r = \dfrac{1}{\sqrt{LC}}\). The inductive reactance at resonance is \(X_L = \omega_r L = \dfrac{L}{\sqrt{LC}} = \sqrt{\dfrac{L}{C}}\).…
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