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JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance

\(512\) identical drops of mercury are charged to a potential of \(2\, V\) each. The drops are joined to form a single drop. The potential of this drop is ......... \(V.\)

  1. A \(128\)
  2. B \(256\)
  3. C \(64\)
  4. D \(144\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(128\)

Step-by-step Solution

Detailed explanation

\(Q =512 q\) Volume \(_{i}=\) Volume \(_{f}\) \(512 \times \frac{4}{3} \pi r^{3}=\frac{4}{3} \pi R^{3}\) \(2^{9} r ^{3}= R ^{3}\) \(R =8 r\) \(2=\frac{ kq }{ r }\) \(V =\frac{ kQ }{ R }=\frac{ k 512 q }{8 r }\) \(V =128\)
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