JEE Mains · Physics · STD 12 - 3. current electricity
Resistance of a wire at \(0^{\circ} \mathrm{C}, 100^{\circ} \mathrm{C}\) and \(t^{\circ} \mathrm{C}\) is found to be \(10 \Omega, 10.2 \Omega\) and \(10.95 \Omega\) respectively. The temperature \(t\) in Kelvin scale is _______.
- A \(735\)
- B \(738\)
- C \(740\)
- D \(748\)
Answer & Solution
Correct Answer
(D) \(748\)
Step-by-step Solution
Detailed explanation
\(\mathrm{R}=\mathrm{R}_0(1+\alpha \Delta \mathrm{T})\) \(\frac{\Delta \mathrm{R}}{\mathrm{R}_0}=\alpha \Delta \mathrm{T}\) Case-I \(0{ }^{\circ} \mathrm{C} \rightarrow 100^{\circ} \mathrm{C}\) \(\frac{10.2-10}{10}=\alpha(100-0)\) Case-II…
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