ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

A body of mass ' \({m}\) ' dropped from a height ' \({h}\) ' reaches the ground with a speed of \(0.8 \sqrt{{gh}}\). The value of workdone by the air-friction is \(.....\,{mgh}\)

  1. A \(0.68\)
  2. B \(1\)
  3. C \(1.64\)
  4. D \(0.64\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.68\)

Step-by-step Solution

Detailed explanation

Work done \(=\) Change in kinetic energy \({W}_{{mg}}+{W}_{{air}-\text { fiction }}=\frac{1}{2} {m}(.8 \sqrt{{gh}})^{2}-\frac{1}{2} {m}(0)^{2}\) \({W}_{\text {air - fiction }}=\frac{.64}{2} {mgh}-{mgh}=0.68 {mgh}\)
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app