JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
\(B _{ X }\) and \(B _{ Y }\) are the magnetic field at the centre of two coils of two coils \(X\) and \(Y\) respectively, each carrying equal current. If coil \(X\) has \(200\) turns and \(20 cm\) radius and coil \(Y\) has \(400\) turns and \(20 cm\) radius, the ratio of \(B _{ X }\) and \(B _{ Y }\) is
- A \(1: 1\)
- B \(1: 2\)
- C \(2: 1\)
- D \(4: 1\)
Answer & Solution
Correct Answer
(B) \(1: 2\)
Step-by-step Solution
Detailed explanation
At centre \(B=N\left(\frac{\mu_{0} i }{2 R}\right)\) \(B_{x}=200\left(\frac{\mu_{0} \dot{i}}{2 \times 20 cm }\right)\) \(B_{y}=400\left(\frac{\mu_{0} i}{2 \times 20 cm }\right)\) \(\frac{ B _{x}}{ B _{y}}=\frac{1}{2}\)
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