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JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
The point of intersection of the normals to the parabola \(y^ 2\, = 4x\) at the ends of its latus rectum is
- A \((0, 2)\)
- B \((3, 0)\)
- C \((0, 3)\)
- D \((2, 0)\)
Answer & Solution
Correct Answer
(B) \((3, 0)\)
Step-by-step Solution
Detailed explanation
We know that point of intersection of the normal to the parabola \(y^ 2\, = 4ax\) at the ends of its latus rectum is \((3a, 0)\) Hence required point of intersection \(= (3, 0)\)
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