The magnetic field in a plane electromagnetic wave is By= (3.5 × 10-7) (1.5 × 103 x+0.5..× 1011 t) T. The corresponding electric field will be _______.

(A) \mathrm{E}_{\mathrm{y}}=1.17 \sin \left(1.5 \times 10^3 \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^1

(C) \mathrm{E}_z=1.17 \sin \left(1.5 \times 10^5 \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}

JEE Mains · Physics · STD 12 - Electromagnetic waves

The magnetic field in a plane electromagnetic wave is \(\mathrm{B}_y=\left(3.5 \times 10^{-7}\right) \sin \left(1.5 \times 10^3 \mathrm{x}+0.5\right.\) \(\left.\times 10^{11} \mathrm{t}\right) \mathrm{T}\). The corresponding electric field will be _______.

Pick an option to check your answer.

Verified Solution

Correct Answer

(B) \(\mathrm{E}_{\mathrm{z}}=105 \sin \left(1.5 \times 10^3 \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\)

Detailed explanation

\(\mathrm{E}_0=\mathrm{B}_0 \mathrm{C}\)

\(\mathrm{E}_0=3 \times 10^8 \times\left(3.5 \times 10^{-7}\right) \sin \left(1.5 \times 10^3 \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right)\)

\(\mathrm{E}_0=105 \sin \left(1.5 \times 10^3 \mathrm{x}+0.5 \times 10^{11} \mathrm{t}\right) \mathrm{Vm}^{-1}\)

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