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JEE Mains · Maths · STD 11 - 4.2 Quadratic equations and inequations

Let \(\alpha, \beta\) be the roots of the equation \(x^2+2 \sqrt{2} x-1=0\). The quadratic equation, whose roots are \(\alpha^4+\beta^4\) and \(\frac{1}{10}\left(\alpha^6+\beta^6\right)\), is :

  1. A \(x^2-190 x+9466=0\)
  2. B \(x^2-195 x+9466=0\)
  3. C \(x^2-195 x+9506=0\)
  4. D \(x^2-180 x+9506=0\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(x^2-195 x+9506=0\)

Step-by-step Solution

Detailed explanation

\( x^2+2 \sqrt{2} x-1=0 \) \( \alpha+\beta=-2 \sqrt{2} \) \( \alpha \beta=-1 \) \( \alpha^4+\beta^4=\left(\alpha^2+\beta^2\right)^2-2 \alpha^2 \beta^2 \) \( =\left((\alpha+\beta)^2-2 \alpha \beta\right)^2-2(\alpha \beta)^2 \) \( =(8+2)^2-2(-1)^2 \) \( =100-2=98 \)…
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