JEE Mains · Physics · STD 11 - System of particles and rotational motion
- JEE Mains 2014
- Medium
- MCQ
A mass \('m'\) is supported by a massless string wound around a uniform hollow cylinder of mass \(m\) and radius \(R\). If the string does not slip on the cylinder, with what acceleration will the mass fall on release?

Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\frac{g}{2}\)
Step-by-step Solution
Detailed explanation
From figure, Acceleration
\(a=R\alpha \) . . . (i)
and \(mg-T=ma\) . . .(ii)
From equation (i) and (ii)
\(T \times R = m{R^a} = m{R^2}\left( {\frac{a}{R}} \right)\)
\(T=ma\)
\(mg-ma=ma\)
\(a=g/2\)
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