JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A mass \('m'\) is supported by a massless string wound around a uniform hollow cylinder of mass \(m\) and radius \(R\). If the string does not slip on the cylinder, with what acceleration will the mass fall on release?
- A \(\frac{g}{2}\)
- B \(g\)
- C \(\;\frac{{5g}}{6}\)
- D \(\;\frac{{2g}}{3}\)
Answer & Solution
Correct Answer
(A) \(\frac{g}{2}\)
Step-by-step Solution
Detailed explanation
From figure, Acceleration \(a=R\alpha \) . . . (i) and \(mg-T=ma\) . . .(ii) From equation (i) and (ii) \(T \times R = m{R^a} = m{R^2}\left( {\frac{a}{R}} \right)\) \(T=ma\) \(mg-ma=ma\) \(a=g/2\)
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