JEE Mains · Physics · STD 12 - 10. Wave optics
In a Young's double slit experiment, light of \(500\, nm\) is used to produce an interference pattern. When the distance between the slits is \(0.05\, mm\), the angular width (in degree) of the fringes formed on the distance screen is close to\(........^o\)
- A \(0.07\)
- B \(0.17\)
- C \(1.7\)
- D \(0.57\)
Answer & Solution
Correct Answer
(D) \(0.57\)
Step-by-step Solution
Detailed explanation
\(\Delta \theta_{0}=\left(\frac{\lambda}{ d } \times \frac{180}{\pi}\right)^{0}\) \(=0.57^{\circ}\)
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