JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
Let \(\mathrm{A}, \mathrm{B}\) and \(\mathrm{C}\) be three points on the parabola \(y^2=6 x\) and let the line segment \(A B\) meet the line \(L\) through \(\mathrm{C}\) parallel to the \(\mathrm{x}\)-axis at the point \(\mathrm{D}\). Let \(\mathrm{M}\) and \(\mathrm{N}\) respectively be the feet of the perpendiculars from \(\mathrm{A}\) and \(\mathrm{B}\) on \(\mathrm{L}\). Then \(\left(\frac{\mathrm{AM} \cdot \mathrm{BN}}{\mathrm{CD}}\right)^2\) is equal to ...........
- A \(63\)
- B \(36\)
- C \(30\)
- D \(70\)
Answer & Solution
Correct Answer
(B) \(36\)
Step-by-step Solution
Detailed explanation
\( \mathrm{m}_{\mathrm{AB}}=\mathrm{m}_{\mathrm{AD}} \) \( \Rightarrow \quad \frac{2}{\mathrm{t}_1+\mathrm{t}_2}=\frac{2 \mathrm{a}\left(\mathrm{t}_1-\mathrm{t}_3\right)}{\mathrm{at}_1^2-\alpha} \)…
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