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JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter

When radiation of wavelength \(\lambda \) is incident on a metallic surface, the stopping potential is \(4.8\) volts. If the same surface is illuminated with radiation of double the wavelength, then the stopping potential becomes \(1.6\) volts. Then the threshold wavelength for the surface is

  1. A \(2\lambda \)
  2. B \(4\lambda \)
  3. C \(6\lambda \)
  4. D \(8\lambda \)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4\lambda \)

Step-by-step Solution

Detailed explanation

(b)By using \(\frac{{hc}}{e}\left( {\frac{1}{\lambda } - \frac{1}{{{\lambda _0}}}} \right) = {V_0}\) \( \Rightarrow \frac{{hc}}{e}\left( {\frac{1}{\lambda } - \frac{1}{{{\lambda _0}}}} \right) = 4.8\)….\(.(i)\) and…
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