JEE Mains · Chemistry · STD 12 - p -Block elements - ll
\(XeF_6\) on partial hydrolysis with water produces a compound \('X'\). The same compound \('X'\) is formed when \(XeF_6\) reacts with silica. The compound \('X'\) is
- A \(XeF_2\)
- B \(XeF_4\)
- C \(XeOF_4\)
- D \(XeO_3\)
Answer & Solution
Correct Answer
(C) \(XeOF_4\)
Step-by-step Solution
Detailed explanation
\(Xe{F_6}\, + \,{H_2}O\, \to \mathop {XeO{F_4}\, + \,2HF}\limits_{(partial\,\,\,hydrolysis)} \) \(Xe{F_6} + 2{H_2}O\, \to Xe{O_2}{F_2}+ \,4HF\) \(Si{O_2}\, + \,2Xe{F_6}\, \to \mathop {\,2XeO{F_4}\, + \,Si{F_4}}\limits_{(Xenoneoxy\,\,\,tetra\,\,fluoride)} \)
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