JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
\(2 \mathrm{SO}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{SO}_{3}(\mathrm{~g})\) The above reaction is carried out in a vessel starting with partial pressure \(\mathrm{P}_{\mathrm{SO}_{2}}=250\, \mathrm{~m}\) \(bar,\) \(\mathrm{P}_{0_{2}}=750 \,\mathrm{~m}\) \(bar\) and \(\mathrm{P}_{\mathrm{SO}_{3}}=0 \,\mathrm{bar}\). When the reaction is complete, the total pressure in the reaction vessel is \(.....\mathrm{m}\) \(bar.\) (Round off to the Nearest Integer).
- A \(875\)
- B \(550\)
- C \(425\)
- D \(930\)
Answer & Solution
Correct Answer
(A) \(875\)
Step-by-step Solution
Detailed explanation
\(\quad\quad\quad\quad\quad2 \mathrm{SO}_{2}(\mathrm{~g})+ \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow 2 \mathrm{So}_{3}(\mathrm{~g})\) \(\text { Initial } \quad 250 \mathrm{~m} \text { bar } \quad750 \mathrm{~m} \text { bar } \quad\quad\quad0\) \(\text { (L.R.) }\)…
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