JEE Mains · Chemistry · STD 11 - 3. Classification of elements and periodicity in properties
Electronic configuration of four elements \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and D are given below :
(A) \(1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^3\)
(B) \(1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^4\)
(C) \(1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^5\)
(D) \(1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^2\)
Which of the following is the correct order of increasing electronegativity (Pauling's scale)?
- A A < D < B < C
- B A < C < B < D
- C A < B < C < D
- D D < A < B < C
Answer & Solution
Correct Answer
(D) D < A < B < C
Step-by-step Solution
Detailed explanation
\(\mathrm{N}:-1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^3\) (Electronegativity \(\left.=3\right)\) \(\mathrm{O}:-1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^4\) (Electronegativity \(=3.5\)) \(\mathrm{F}:-1 \mathrm{~s}^2 2 \mathrm{~s}^2 2 \mathrm{p}^5\) (Electronegativity…
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