JEE Mains · Chemistry · STD 12 - p -Block elements - ll
\(XeF _4\) reacts with \(SbF _5\) to form \({\left[ XeF _{ m }\right]^{ n +}\left[ SbF _{ y }\right]^{ z- }}\) \(m + n + y + z =.......\).
- A \(10\)
- B \(11\)
- C \(12\)
- D \(13\)
Answer & Solution
Correct Answer
(B) \(11\)
Step-by-step Solution
Detailed explanation
\(XeF _4+ SbF _5 \rightarrow\left[ XeF _3\right]^{+}\left[ SbF _6\right]^{-}\) \(m =3\) \(n =1\) \(y =6\) \(z =1\) \(m + n + y + z =11\)
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