JEE Mains · Physics · STD 12 -6. Electromagnetic induction
The arm \(P Q\) of a rectangular conductor is moving from \(x=0\) to \(x=2 b\) outwards and then inwards from \(x=2 b\) to \(x=0\) as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from \(x=0\) to \(x=b\). Identify the graph showing the variation of different quantities with distance.
- A \(A-\)Flux, \(B-EMF, C-\)Power dissipated
- B \(A-\)Power dissipated, \(B-\)Flux, \(C-EMF\)
- C \(A-Flux, B-\)Power, dissipated, \(C-EMF\)
- D \(A-EMF, B-\)Power dissipeated, \(C-\)Flux
Answer & Solution
Correct Answer
(A) \(A-\)Flux, \(B-EMF, C-\)Power dissipated
Step-by-step Solution
Detailed explanation
As rod moves in field area increases upto \(x=b\) then field is absent and again flux is generated on return journey from \(x=b\) to \(x=0\). Thus plot \(A\) for flux. \(\Rightarrow e=-\frac{d \phi}{d t} \Rightarrow\) curve \(B\) for \(e m f\) \(\Rightarrow\) Power dissipated…
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