JEE Mains · Physics · STD 12 -Electromagnetic induction
- JEE Mains 2021
- Hard
- MCQ
The arm \(P Q\) of a rectangular conductor is moving from \(x=0\) to \(x=2 b\) outwards and then inwards from \(x=2 b\) to \(x=0\) as shown in the figure. A uniform magnetic field perpendicular to the plane is acting from \(x=0\) to \(x=b\). Identify the graph showing the variation of different quantities with distance.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(A-\)Flux, \(B-EMF, C-\)Power dissipated
Step-by-step Solution
Detailed explanation
As rod moves in field area increases upto \(x=b\) then field is absent and again flux is generated on return journey from \(x=b\) to \(x=0\). Thus plot \(A\) for flux.
\(\Rightarrow e=-\frac{d \phi}{d t} \Rightarrow\) curve \(B\) for \(e m f\)
\(\Rightarrow\) Power dissipated \(=v i \Rightarrow\) curve \(C\) for power dissipated
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